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$\int \frac{d x}{\sqrt{1 - 6 x}} = f (x) + c$ হলে, f(x) = ?

dsuc.created: 1 year ago | dsuc.updated: 1 week ago

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\frac{1}{4} {(1 - 6 x)}^{\frac{2}{3}}

- \frac{1}{4} {(1 - 6 x)}^{\frac{2}{3}}

- \frac{1}{4} {(1 - 6 x)}^{\frac{3}{2}}

\frac{1}{4} {(1 - 6 x)}^{\frac{3}{2}}

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$\int \frac{d x}{\sqrt{1 - 6 x}} = f (x) + c$ হলে, f(x) = ?

| এর সঠিক উত্তর $- \frac{1}{4} {(1 - 6 x)}^{\frac{2}{3}}$

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