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Length of each equal side of an isosceles triangle is 10cm and the included angle between those two sides is 45°. Find the area of the triangle.
Let, x be the perpendicular drawn from the vertex of the triangle
We know,
sin 45°=PerpendicularHypotenuse⇒12=x10 ∴x=102
Now, we know area of triangle
=12×base×height=12×10×102=502=25×2×22=252 ans.
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