Minhaz and Alam can complete a work in 18 days . After working together for 12 days Minhaz stops and Alam competes the remaining work in 8 days. In how many days can Minhaz complete the work if he works alone?

dsuc.created: 2 years ago | dsuc.updated: 2 years ago

dsuc.updated: 2 years ago

In 18 days, they can complete = 1 parts of work

In 1 days, they can complete= $\frac{1}{18}$ parts of work

In 12 days, they can complete = $\frac{12}{18} = \frac{2}{3}$ parts of work

Remaining work $= (1 - \frac{2}{3}) = (\frac{3 - 2}{3}) = \frac{1}{3}$

Now, $\frac{1}{3}$ parts of work is done by Alam in = 8 days

1 or complete parts of work is done by Alam in= $8 \times 3 = 24 d a y s$

Alam can do $\frac{1}{24}$ parts of work in 1 day.

Minhaz can do in 1 day = $(\frac{1}{18} - \frac{1}{24}) = (\frac{4 - 3}{72}) = \frac{1}{72}$ parts

That means $\frac{1}{72}$ parts of work is done by Minhaz in 1 day

1 or complete parts of work is done by Minhaz in $\frac{72 \times 1}{1} = 72 d a y$

He can do the whole work alone in 72 days. ans.

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