Job

A bag contains 5 red and 3 green balls. Another bag contains 4 red and 6 green balls. If one ball is drawn from each bag. Find the probability that one ball is red and one is green.

(Probability)

dsuc.created: 2 years ago | dsuc.updated: 1 year ago
dsuc.updated: 1 year ago

In bag 1: There are 5 red balls and 3 green balls.

In bag 2: There are 4 red balls and 6 green balls.

Now,

In case 1, the probability of getting red ball from bag I and green ball from bag

2=55+3×64+6=56×610=3060

And, In case 2, the probability of getting green ball from bag I and red ball from bag

2=38×410=1280

Probability of getting 1 red ball and 1 green ball = 3080+1280=30+1280=4280=2140 (answer).

1 year ago

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